[BOŞ_SES] Hello!

This differential in our preceding session

We found a method for solving equations of the team.

The essence of this method y a

z was to make a conversion in converting to the diagonal.

Bring a diagonal structure of the unknown which one single, one in each

We solved the unknown and brought into the equation and then we come back to y.

Here we proceed in a different way, but we still do the same

The solution under an initial condition that the equation again.

I want to remind you to start with.

We did in the first subdivision of this section,

The only unknowns in the equation solving method recall once more.

This method of interpreting a little different direction,

We'll get here the method we developed.

Again, the more a function here.

To a constant.

This is the initial condition.

Solution consisted of the following steps.

We find lean solution.

It is not the usual solution to over a x.

Indeed, we see easily that this equation is situated, it provides.

This actually happens to remind you again but I think

and because we need to emphasize here that the matrix function

It will be inspired to capture the air.

Special solutions was the second step.

Here we go again with optimism in a special solution.

We say: since this is a fairly simple solution contains information, let's use it.

Lean solutions now we multiply the unknown unknown function.

If you go to this starting,

284 pages in even-numbered pages.

We are on the left side instead of taking the derivative of this y.

y derivative course this e derivative.

plus a once u e to the ax hit the second first time

If there is a time derivative of the year on the right side.

So once again a plus where the function h.

Again, with the first customer left, the right first term

taking each other and we are getting a supremely simple equation for u.

Differential equations are not.

But there are only derivatives of derivatives.

Thus, the problem is coming to an integration problem.

We also find that taking the integration within certain limits.

This means that custom solutions are able to achieve this structure.

e to u multiplied by AX.

U here.

We also can write equivalent structure, taking the ax to them inside.

As you can see where x minus x h with a term of üssül

Coming to the product structure.

It is a grace and an equal representation in its own benefit.

We also add a simple solution for this particular solution we find a general solution.

Lean solution to secure a higher multiplying AX.

This is a simple solution.

And wherein the terms,

The term special solutions.

To find the general solution for x instead of y zero

sheep given year should not equal to zero.

This z, showing the flexibility of its c.

We will not be able to provide an initial condition c not here.

x instead

Put the car is staying here only to zero.

We have seen a definite integrals Integral also getting benefit earlier.

In this way, but not necessarily be zero unless x

Put the x base means that this term goes to zero zero drops.

This is not something the integration and simplifies our work.

Inasmuch as the value of y was equal to c at zero.

He also provided.

y is zero.

We find in the c.

So y can be brought to this structure,

instead of using the car where y is zero.

How is that here were two equivalent structures for custom solutions.

Here, via e ax throwing into a solution can be achieved in this way.

This matrix equation is to find our inspiration now.

Now that we are over the moon with y h plus the sheer number,

a component with a number of functions,

We found the solution with digital function,

Let the vector equation for the same solution.

E to the vector equation ax indeed,

that's where you see the matrix function, the name of the method comes from here,

Spirit also comes from here, with as yet unknown

We see now that there is a simple solution that we multiply by the constant vector c.

See our equation moon base

simple equation y equals a times.

Once the base year minus a simple function

As you can see hit the base year for which a fixed again

prevent falls and where the lack of square matrices

Because a'yl AX product via e ai no mater where you will have.

We put them in front of where the ax to c occurs.

Once again there is a YHA.

As you can see them taking each other.

So said a solution to this matrix.

We're going to have generalized solution we found in this digital function matrix.

Since, in the same way as we found a simple solution,

Using the same here as we inspired yh'y

e to the special solution from a matrix ax times x number of times

We assume again that the optimism of the product,

Put in it really to end

again it coming down to a simple equation results in simplification.

Already the biggest feature of the square matrix

The sequence is not significant as plain numbers and in all processes

it can be done any time of the collection of the product.

Quite a list at the beginning of this section,

We saw quite a list giving the privilege of a matrix.

So here's just the same numerical functions

the only remains of an integral business.

The base where the same numeric functions

as is, that is to say in the same way as in numeric functions

like going to the integral of the vector matrix multiplication.

The only difference here to ax over a matrix, a matrix function, a vector h.

In detail, it is giving a vector.

I still remember the special solution.

Ax'l u e to the special resolution was the product here

we put the ax to them.

Also here.

So we find special solutions.

General solution of the same so there's no need to even go through it.

We could have written after nephew.

Because the matrix, square matrix acts like the same numbers all at this.

And where do we get the same solution.

We kept it a little more general.

Scratch scratch, albeit not in a x x comes here a number of zero counts.

Now the whole issue came to that.

How do we calculate via e ai.

EUR for the calculation of the above, given the resources right here.

We know that.

If a lamp in one of the eigenvalues,

two lambda lambda n, the eigenvalues of the e a e two,

The matrix diagonalization most au q

e, including those to each column

köşegenleştiriy in which he functions.

So it is a matrix function of it going backwards

diagonal matrix with q as health soll

We know it's equally collision,

where they were given in these resources.

That work will be extremely simplified, let's see an example.

Let's take the previous example again the same.

Two unknowns, starting conditions are the same,

A matrix of identical right and it refers to it being the same.

We have found the eigenvalues of this matrix had been minus one and three.

We find the eigenvalues.

To bring paint to the unit eigenvectors matrix is symmetric

We know that makes it easy to calculate the Q and vice versa.

So for example we do here is completely the same as the previous one.

Now we come to the critical and different directions.

e to the e to the lambda once on the diagonal means Axe x

e to the x Place the right lamp twice in Q

Q minus comes from the left with a shock.

So it comes down to a matrix multiplication.

See how easy it is.

So if you find the eigenvalues of matrix as a hundred computers,

You find the eigenvalues, you create the Q,

You create the Q minus 1, the business remains a matrix multiplication.

You close your eyes that you just needed no computer command, bong

seen already how we could do this with MATLAB

We will give you the commands.

If we make this product, do the right product before.

We found that, had left matrix.

This matrix is the challenge of the multiplication results we have achieved here.

E to where we know the simple solution

With this year will hit zero, the simple solution here.

We have found the formula for a private solution.

E to the base where special solutions Axe

the integral of the product of HX base, we call it the base.

Let's do this multiplication.

We do this multiplication.

These are all things that you know as a bit time-consuming but extremely simple operations,

You do longitudinal multiplication, we found here.

We take this to the integral.

This means that integration means you get here integral.

We find that the zero and the value of x x base.

We came here because a change as cons

In order to get rid of it negative.

And that we obtain it, we stood with the ax to them,

e to the minus x over Axa we calculate it.

e to the minus Axe we achieved by replacing the x minus x base.

This integration is obtained after such account.

We stood with Axe with Ax'l to take it to higher,

wherein a multiplication result obtained from the special solution.

So all of these actions can be done blindly at all.

This will give the code with MATLAB software already, you'll see.

Here we find an overall solution,

As you can see, this consists of a collection and comes into this shape.

This equation a bit of work simplification,

If you divide a split coming here and getting four

results we have going here.

That we found earlier

Compared same solutions that we see now.

We see that the same solution here.

You can note the page.

On page 300 the same, exact solutions

giving us.

Now I want to take a break here.

This process is progressing in a very systematic way.

After that, I want to give an example.

This is a second order differential equation and this is a significant

differential equations, turning it into equation

This top exponent of this equation we see the team

by calculating that function matrix method and more

We will calculate the diagonalization method we have seen before.