And I what analyze if this consistent so

I can do a KVL around the outer loop.

And because I want to solve for i sub D1.

And that was minus 10 plus this voltage drop across the resistor,

which is a 1,000 times i sub D1, plus 5 equal 0.

And if I solve for it, I'm going to get, from this equation,

i sub D1 is equal to 0.005 amps, which is positive.

Well, that's good, because that is consistent with a diode conducting.

Diode conducting, i sub D has to be positive.

So, that is consistent.

Now lets look at the other one,

I've, we want to find out if i sub D2 is also positive.

So I can do a KVL around this one, this loop right there.

I have minus 5 plus 2,000 times i sub D2 equals 0 and

if I solve for that I get I sub D2 is equal to 5

over 2000 and that's amps and that's positive.

Again this is supposed to be conducting and it is consistent,

because in a conducting state the diode current has to be positive.