this is going to not be the most efficient power transfer, so that's not a

good solution. the solution to this is going to be to

take two of these speakers, connect them in series, like this, and that gives you

16 ohms. And then take the other pair, connect

them in series. That's another 16-ohm impedance.

And then if I connect these two pairs of speakers in parallel, I have 16 in

parallel with 16, that's going to give me 8 ohms.

So that's the, the way to connect these speakers together, so I get maximum power

transfer from my 8 ohm output impedance amplifier, to my array of 4 8 ohm

loudspeakers. Okay, now before we go on and talk about

[UNKNOWN] amps, just to complete the set of sources we're going to be dealing

with, I need to talk a little bit about current sources.

Now, let's start by talking about the ideal current source.

Now, it's just what it says. a cur, a source of current is, is just

something that if I connect the load resister to it, it's going to force its

current through that resister regardless of the value of the load resister.

And so, that means that the ideal current source can generate any voltage that you

want. So, if I take, let's say I had a 1 amp

current source here, and I connected a 100 ohm load resistor to it.

That means that this current source would have to generate 100 volts to force, to

continue forcing its 1 amp through this 100 ohm resistor.

Now just like voltage sources current sources, real current sources are non

ideal, that means they could produce only so much voltage.

There's a limit to how much voltage they can produce.

So, the way to represent a real current source is we add an internal resistance

in parallel with the ideal source. And so, this pair of terminals is looking

into the real current source. There's this internal resistance that we

can't separate from the current source. It's internal to it, it's part of it,

it's, it's there you're stuck with it. So now, if I take a look at at this and I

ask what is the maximum voltage I can generate across a load.