Which we have s for this and

we have (1.0 x 10 to -5) squared for

this, and that will give me s = 2.2 x 10

to -20 divided by 1.0 x 10 to -10.

Because -5 squared is to -10.

This will give me a solubility of

2.2 x 10 to the -10.

That will be the concentration of the copper hydroxide that would dissolve.

Now, what did we learn in this unit?

We learned that if you have a solution that contains a common ion,

it will always decrease the solubility of that salt in the solution.

What I've written up here, what we obtained for

the value of copper hydroxide solubility in pure water.

1.9 x 10 to the -7.

This is one 2.2 x 10 to the -10.

That is lower.

It has decreased the solubility by having a common ion present in solution.